For continuous compounding, ert gives the multiplier for your money, given an interest rate r and a time interval t.
You want to find t for r=6% and ert=2.
2 = e.06t
Ln[2] = .06t
Ln[2]/.06 = t
.693147/.06 = t = 11.55
It will take 11.55 years at 6% per year to double your money.
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"9 years" has nothing to do with the problem of doubling your money. Nor does $3000. The multiplier for 9 years is
e(.06)(9) = e.54 ≈ 1.716007
$3000 will be worth $3000*1.716007 = $5148.02 after 9 years.
You want to find t for r=6% and ert=2.
2 = e.06t
Ln[2] = .06t
Ln[2]/.06 = t
.693147/.06 = t = 11.55
It will take 11.55 years at 6% per year to double your money.
_____
"9 years" has nothing to do with the problem of doubling your money. Nor does $3000. The multiplier for 9 years is
e(.06)(9) = e.54 ≈ 1.716007
$3000 will be worth $3000*1.716007 = $5148.02 after 9 years.