For every dollar there are 10 dimes. And every 20 nickels make a dollar as well. 10 dimes + 20 nickels are 30 coins, adding up to two dollars. 25 dimes ($2.50) + 15 nickels ($0.75) would make a total of 40 coins adding up to $3.25 Therefore there is a total of 25 dimes.
Your piggy bank has a total of 40 coins in it; some are dimes and some are nickels. If you have a total of $3.25, how many dimes do you have?
You can often work this sort of problem in your head. If all 40 coins were nickels, the amount would be $2.00. You have $1.25 more than that. Trading one of the nickels for a dime adds $.05 to the value without changing the number of coins. To add $1.25 to the value, you must trade for $1.25/$.05 = 25 dimes.
Here is the lazy algebra way. A system of equations
X = dimes
Y = nickles
All to pennies
- 5(X + Y = 40)
10X + 5Y = 325
- 5X - 5Y = -200
10X + 5Y = 325
------+
5X = 125
X = 25
which is your 25 dimes
X = dimes
Y = nickles
All to pennies
- 5(X + Y = 40)
10X + 5Y = 325
- 5X - 5Y = -200
10X + 5Y = 325
------+
5X = 125
X = 25
which is your 25 dimes